Identify Z in the following series C2H5OHPBr3−−−→Xalc.KOH−−−−−→Ydil.H2SO4−−−−−−→Z.
A
CH2=CH2
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B
CH3CH2OH
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C
CH3−CH2−O−CH2−CH3
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D
None
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Solution
The correct option is BCH3CH2OH
When ethyl alcohol reacts with PBr3 it forms ethyl bromide as a product which on reaction with alc KOH undergoes β-elimination reaction to form ethene as a product. The ethene on reaction with dil. H2SO4 undergoes hydrolysis to form ethyl alcohol as a product.