Question

If $0.01M$ solution of an electrolyte has a resistance of $40$ ohms in a cell having a cell constant $0.4$ $c{m}^{-1}$ then its molar conductance would be:

• A. $10$${}^4$
• B. $10$${}^3$
• C. $10$${}^2$
• D. $10$

Answer 1

The correct option is B $10$${}^3$

The molar conductance $=\frac{\text{conductance}}{\text{molar-concentration}}$

$=\frac{1}{\text{resistance}}\times \frac{\text{cell-constant}}{{\text{concentration (in mol cm}}^{-3})}$

$=\frac{1}{40}\times \frac{0.4}{0.01\times {10}^{-3}}={10}^3{\Omega }^{-1}c{m}^{2}mo{l}^{-1}$

Hence, option B is correct.