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Question

When a conductance cell was filled with 0.0025 M solution of an electrolyte, its resistance was 200 ohm. What will be the specific resistance (in Ω) of the electrolyte?

Given:

Length of cell =100 cm

Cross-sectional area =1.12×10−4 cm2.

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Solution

The correct option is **C** 2.24×10−4

From ohm's law

V=I×R

R=VI

200=Specific resistance×1001.12×10−4

Specific resistance, ρ=2.24×10−4

From ohm's law

V=I×R

R=VI

V:Potential differenceR:Electrical resistanceI:Current

The electrical resistance of a conductor is directly proportional to its length (l) and inversely proportional to its area of cross section (A).

R∝lA

R=ρ×lA

Where,

ρ is constant of proportionality

This constant of proportionality is called resistivity or specific resistance.

Specific resistance, ρ=R×Al

200=Specific resistance×1001.12×10−4

Specific resistance, ρ=2.24×10−4

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