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Question

If 0.224L of H2 gas is formed at the cathode, the volume of O2 gas formed at the anode under identical conditions is:

A
0.224L
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B
0.448L
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C
0.112L
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D
1.12L
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Solution

The correct option is D 0.112L
H2OH2+12O2.

From the above equation, it is clear that the volume of O2 formed will be half of the formation of H2.

Since, volume of H2 formed =0.224L

So, volume of O2 formed =0.2242 = 0.112 L

Hence, the correct answer is an option C.

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