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Inductive Effect

If 0.5 mol ...

Question

If $0.5$ mol of $B a C l_{2}$ is mixed with $0.2$ mol of $N a_{3} P O_{4}$ , the maximum number of mol of $B a_{3} (P O_{4})_{2}$ that can be formed is:

0.7

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0.5

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0.2

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0.1

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Solution

The correct option is D $0.1$
$3 B a C l_{2} + 2 N a_{3} P O_{4} \to B a_{3} (P O_{4})_{2} + 6 N a C l$
$0.5 m o l 0.2 m o l x m o l$
First find which is the limiting reagent ?
$\frac{0.5}{3} = \frac{1}{6} \frac{0.2}{2} = \frac{1}{10}$
Therefore ,
$N a_{3} P O_{4}$ is the limiting reagent
$\frac{1}{10} = \frac{x}{1}$
$x = 0.1 m o l$

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