wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 0.5 moles of BaCl2 is mixed with 0.2 moles of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is:
The corresponding balanced reaction is: 3BaCl2+2Na3PO4Ba3(PO4)2+6NaCl

A
0.7 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.2 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.1 mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.1 mol
The given balanced reaction is,
3BaCl2+2Na3PO4Ba3(PO4)2+6NaCl
So, from the balanced reaction,
3 mol of BaCl2 reacts with 2 mol of Na3PO4 to give 1 mol of Ba3(PO4)2
The amount of BaCl2 given here is 0.5 mol.
The amount of Na3PO4 needed to completely react with 0.5 mol BaCl2
=23×0.5 mol = 0.33 mol
But the amount of Na3PO4 given is 0.2 mol. Thus, Na3PO4 is the limiting reagent here.
Hence, the maximum number of moles of Ba3(PO4)2 that can be formed:
12×0.2 mol = 0.1 mol

flag
Suggest Corrections
thumbs-up
32
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon