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Question

If 0.5 moles of BaCl2 is mixed with 0.2 moles of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is:
The corresponding balanced reaction is: 3BaCl2+2Na3PO4Ba3(PO4)2+6NaCl

A
0.7 mol
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B
0.5 mol
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C
0.2 mol
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D
0.1 mol
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Solution

The correct option is D 0.1 mol
The given balanced reaction is,
3BaCl2+2Na3PO4Ba3(PO4)2+6NaCl
So, from the balanced reaction,
3 mol of BaCl2 reacts with 2 mol of Na3PO4 to give 1 mol of Ba3(PO4)2
The amount of BaCl2 given here is 0.5 mol.
The amount of Na3PO4 needed to completely react with 0.5 mol BaCl2
=23×0.5 mol = 0.33 mol
But the amount of Na3PO4 given is 0.2 mol. Thus, Na3PO4 is the limiting reagent here.
Hence, the maximum number of moles of Ba3(PO4)2 that can be formed:
12×0.2 mol = 0.1 mol

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