If 0.5 moles of BaCl2 is mixed with 0.20 moles of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is :
A
0.1
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B
0.2
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C
0.5
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D
0.7
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Solution
The correct option is C0.1 3BaCl23mol+2Na3PO42mol→6NaCl6mol+Ba3(PO4)21mol Given, 0.5 mol of BaCl2 and 0.2 mol of Na3PO4 are mixed. 2 mol of Na3PO4⇒3 mol of BaCl2 0.2 mol of Na3PO4⇒0.3 mol of BaCl2 ∴Na3PO4 is the limiting reagent. ∴2 mol of Na2PO4⇒1 mol of Ba3(PO4)2 0.2 mol of Na3PO4⇒0.1 mol of Ba3(PO4)2