If 0 < a < b,then limnāā(bn+an)1/n is equal to
e
a
b
1
limn→∞b(1+(ab)n)1/n
We can see that the expression which is multiplies with "b" becomes limx→0b(1+x)x Which we know is equal to 1. = b.1
=b
If 0 < a < b,then limn→∞(bn+an)1/n is equal to