If 0- a - b- then lim n - b n - a n 1 - n is equal toA- aB- bC- None of theseD- e

The correct option is B bn→∞limb ( 1+ ( a/b )^n )^1/n =b(1+0)^0 =b ...

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Standard Limits to Remove Indeterminate Form

If 0< a < b, ...

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If 0 < a < b, then $l i m n \to \infty (b^{n} + a^{n})^{1 / n}$ is equal to

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None of these

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If 0 < a < b,then $lim n \to \infty (b^{n} + a^{n})^{1 / n}$ is equal to

${lim}_{n \to \infty} [\frac{1}{1 - n^{2}} + \frac{2}{1 - n^{2}} + \dots + \frac{n}{1 - n^{2}}]$ is equal to

Δ = ∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} c^{2} & b c & b + c c^{2} a^{2} & c a & c + a a^{2} b^{2} & a b & a + b \end{matrix} ∣ ∣ ∣ ∣ ∣

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\int (s i n^{- 1} x) (Φ (x)) d x

a = l o g_{24} 12, b = l o g_{36} 24, c = l o g_{48} 36

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