If 0≤x≤3π,0≤y≤3π and cosx.siny=1, then the possible number of ordered pair (x,y) is:
A
4
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B
8
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C
6
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D
12
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Solution
The correct option is C 6 cosx.siny=1 we know −1≤cosx,siny≤1 Hence, cosx=1,siny=1 or cosx=−1,siny=−1 thus solution in the given interval is, x=0,2π,y=π2,5π2 or x=π,3π,y=3π2 Thus possible number of ordered pair is, 2×2+2×1=6 Hence, option 'C' is correct.