If $0 < x < \frac{π}{2}$ , then the largest angle of a triangle whose sides are $1$ , $sin x$ , $cos x$ is:

π / 3

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π / 2

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x

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\frac{π}{2} - x

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Solution

The correct option is C $π / 2$
Consider the above image. Since the hypotenuse is 1, which is the largest side, the angle opposite to it will be the largest angle, and since $s i n θ = 1$ implies $θ = 90^{0}$ , therefore, it is a right angled triangle.

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