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Odd Extension of a Function

If 00 < x < 9...

Question

If 0⁰ < x < 90^o and cos then log₁₀ sin x + log ₁₀ cos x + log ₁₀ tan x is equal to

A

\frac{3}{\sqrt{10}}

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B

\frac{- 3}{\sqrt{10}}

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C

1

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D

-1

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Solution

The correct option is D
-1

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Similar questions

0 < x < \frac{π}{2}

cos x = \frac{3}{\sqrt{10}}

, then the value of

{log}_{10} sin x + {log}_{10} cos x + {log}_{10} tan x

Q. If 0⁰ < x < 90^o and cos

then log₁₀ sin x + log ₁₀ cos x + log ₁₀ tan x is equal to

0^{o} < x^{o} < 90^{o}

cos x = \frac{3}{\sqrt{10}}

log sin x + log cos x + log tan x

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{{log}_{10} n - 1}{2}

, then the value of

\frac{n}{3}

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{({log}_{10} n) - 1}{2},

then the value of

n

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