if 1:8 is the ratio of mass of hydrogen to the mass of oxygen in the compound water,then how much hydrogen will decompose 8 gram of oxygen?

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Solution

$2 H + \frac{1}{2} O_{2} \to H_{2} O 2 g 16 g 18 g A s p e r t h e l a w o f c o n s e r v a t i o n o f m a s s M a s s o f r e a c \tan t = m a s s o f p r o d u c t 16 g o x y g e n n e e d s 2 g h y d r o g e n S o 8 g o x y g e n n e e d s 1 g h y d r o g e n$

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if 1:8 is the ratio of mass of hydrogen to the mass of oxygen in the compound water,then how much hydrogen will decompose 8 gram of oxygen?

2 H +12 O2 →H2O 2 g 16 g 18 g As per the law of conservation of massMassof reactant = mass of product16 g oxygen needs 2 g hydrogenSo 8 g oxygen needs 1g hydrogen

$2 H + \frac{1}{2} O_{2} \to H_{2} O 2 g 16 g 18 g A s p e r t h e l a w o f c o n s e r v a t i o n o f m a s s M a s s o f r e a c \tan t = m a s s o f p r o d u c t 16 g o x y g e n n e e d s 2 g h y d r o g e n S o 8 g o x y g e n n e e d s 1 g h y d r o g e n$