If $1 A B + C C A = 295$ , then the value of $B$ is

9

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6

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8

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4

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Solution

The correct option is C $8$
Given, $1 A B + C C A = 295$ .
Then $(100 + A B) + (100 C + C A) = 295$
or, $100 (C + 1) + A B + C A = 295$
$\Rightarrow C + 1 = 2$ and $A B + C A = 95$
$∴ C = 1$ and $A B + 1 A = 95$ .....(1)
From (1) we get,
$A B + 1 A = 95$
or, $A B + 10 + A = 95$
or, $A B + A = 85$
It is clear that $A$ must be $> 6$ , let us take $A = 7$ then we have $B = 8$ .
So, $B = 8$ .

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