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Question

If (1+i)(1+2i)(1+3i)......(1+ni) = a+ib, then 2.5.10.....(1+n2) is equal to

 



Solution

The correct option is C


we have

(1+i)(1+2i)(1+3i)......(1+ni) = a+ib   .......(i)

(1+i)(1+2i)(1+3i)......(1+ni) = a-ib ........(ii)

Multiplying (i) and (ii), we get 2.5.10.....(1+n2) = a2+b2

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