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Question

If 1 is a root of the equations ay2+ay+3=0 and y2+y+b=0, then ab equals:

A
3
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B
72
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C
6
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D
3
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Solution

The correct option is A 3
ay2+ay+3=0
as 1 is root then
a(1)2+a(1)+3=0
a+a=3
2a=3
a=32

y2+y+b=0
(1)2+1+b=0
2+b=0
b=2

ab=32×2=3

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