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Question

​if 1 mole of pottassium chromate and 1 mole of lead nitrate gives 1 mole of lead chromate and 2 moles of pottassium nitrate, how many grams of lead chromate will beobtained formed using 7g of potassium chromate and 10g of lead nitrate.

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Solution

K2CrO4 + Pb(NO3)2 PbCrO4 + 2 KNO3194 g 331 g 323 g 2 (101) = 202 g194 g of potassium chromate reacts with 331 g lead nitrateSo 7 g of potassium chromate reacts with = 331194 × 7 = 11.94 g of lead nitrateSince the amount of lead nitrate given is 10 g, it acts as a limiting reagent.331 g of lead nitrate gives 323 g of lead chromate10 g of lead nitrate gives = 323331 × 10 = 9.76 g of leadchromate is formed

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