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Question

If 1, ω, ω2are the cube roots of unity, then the value of aω2+b+cω+ dω2a+bω+ cω2+d (a, b, c, d R) is

A
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B
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C
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D
1
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Solution

The correct option is A
S = aω2+b+cω+ dω2a+bω+ cω2+d= ω2 (aω2+b+cω+ dω2)(aω2+ bω3+ cω4+ dω2)
= ω2 (aω2+b+cω+ dω2)(aω2+b+cω+ dω2)[ω3=1]
= ω2= 1ω

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