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B
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C
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D
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Solution
The correct option is D C1C0+2C1C1+3C3C2+.....nCnCn−1=n11+2.1(1−1)1−2n1+3.n(n−1)(−2)1.2.31(n−1)1.2+....+n.1n1=n+(n−1)+(n−2)+....+1=1+2+3+....+n=n(n+1)2