If 10n+3×4n+2+λ is divisible by 9 for all nepsilonN, then the least positive integral value of λ is
5
(a) Let P(n) : 10n+3×4n+2+λ is divisible by 9, for all nϵN
For n = 1, the given statement is also true 101+3.41+2+λ is divisible by 9
∵=10+3.64+λ=10+192+λ
=202λ
If (202 + λ) is divisible by 9, then the least value of k must be 5
∵202+5=207 is divisible by 9
⇒2079=23
Hence, the least value of k is 5.