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Question

If 10n+3×4n+2+λ is divisible by 9 for all nepsilonN, then the least positive integral value of λ is


A

5

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B

3

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C

7

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D

1

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Solution

The correct option is A

5


(a) Let P(n) : 10n+3×4n+2+λ is divisible by 9, for all nϵN

For n = 1, the given statement is also true 101+3.41+2+λ is divisible by 9

=10+3.64+λ=10+192+λ

=202λ

If (202 + λ) is divisible by 9, then the least value of k must be 5

202+5=207 is divisible by 9

2079=23

Hence, the least value of k is 5.


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