Question

If $10$% of the main current is to be passed through the moving coil galvanometer of resistance $99\Omega$, then the required shunt resistance will be :

• A. $9.9\Omega$
• B. $10\Omega$
• C. $11\Omega$
• D. $9\Omega$

Answer 1

The correct option is C $11\Omega$

Here, $I_g=\frac{I}{10},G=99\Omega$
$\because$ The shunt, $S=\frac{I_g}{I-I_g}\cdot G$
$\therefore S=\frac{I/10}{I-\frac{I}{10}}\times 99$
$\Rightarrow S=11\Omega$.