Question

The value of shunt resistance, in order to pass $10\%$ of the main current in the galvanometer of resistance $99\Omega$, will be

• A. $9.9\Omega$
• B. $10\Omega$
• C. $11\Omega$
• D. $9\Omega$

Answer 1

Answer: (C)

$11\Omega$

$0.1I\times 99=0.9I\times R_s$
$\Rightarrow R_s=11\Omega$