Question

If 100.0 J of energy is added to 50.0 g of Cu, initially at ${25.0}^{o}C$, what will be the final temperature? (Specific heat capacity = 0.382 J/ C.g )

• A. ${31.2}^{o}C$
• B. ${30.24}^{o}C$
• C. ${25.2}^{o}C$
• D. ${25.19}^{o}C$
• E. ${19.8}^{o}C$

Answer 1

Answer: (B)

${30.24}^{o}C$

let T deg C be the final temperature.
$q=mS\Delta T$
$q=100.0$ J = energy added
$m=50.0$ g = mass of Cu
$S=0.382$ J/C.g = the specific heat of Cu
$\Delta T=T-25.0$ = temperature difference.
Substite values in the above equation.
$100.0=50.0\times 0.382\times (T-25.0)$
$5.235=T-25.0$
$T={30.24}^{o}C$