If $100$ calorie of heat are added to the system and a work of $50$ calorie is done on the system, calculate the energy change of the system.

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Solution

Heat absorbed, $q = 100 c a l$
Work done on the system, $w = + 50 c a l$
Applying the first law of thermodynamics
$Δ U = q + w = (100 + 50) = 150$ calorie

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If 100 calorie of heat are added to the system and a work of 50 calorie is done on the system, calculate the energy change of the system.

Heat absorbed, q=100calWork done on the system, w=+50calApplying the first law of thermodynamicsΔU=q+w=(100+50)=150 calorie

If $100$ calorie of heat are added to the system and a work of $50$ calorie is done on the system, calculate the energy change of the system.

Heat absorbed, $q = 100 c a l$
Work done on the system, $w = + 50 c a l$
Applying the first law of thermodynamics
$Δ U = q + w = (100 + 50) = 150$ calorie