If 10^2y=25 then 10^-yequals?

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Solution

Given 10^2y = 25
⇒ (10^y)² = 5²
⇒ (10^y) = 5
⇒ (10^y)^-1 = (5)^-1
∴ 10^-^y = (5)^-1= 1/5 Ans

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