If 1050 J of heat is required to increase the temperature of 15 kg of substance from 25-C to 35-C- Find the thermal capacity and water equivalent of the substance-

Given: m=15kg=15×10^3g, Δ T=(35 25) #176;C=10 #176;C, Q=1050J we know, Q=mCΔ T , where C is specific heat capacityHence, C= QmΔ T=105015×10^3× ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Specific Heat Capacity

If 1050 J of ...

Question

If 1050 J of heat is required to increase the temperature of 15 kg of substance from $25^{\circ} C$ to $35^{\circ} C$ . Find the thermal capacity and water equivalent of the substance?

Open in App

Solution

Given:
$m = 15 k g = 15 \times 10^{3} g, Δ T = (35 - 25) ° C = 10 ° C, Q = 1050 J$
we know, $Q = m C Δ T$ , where C is specific heat capacity
Hence, $C = \frac{Q}{m Δ T} = \frac{1050}{15 \times 10^{3} \times 10} = 7 \times 10^{- 3} J g^{- 1} ° C^{- 1}$

Thermal heat capcity $= m C = 15 \times 10^{3} \times 7 \times 10^{- 3} = 105 J ° C^{- 1}$
And, water equivalent $= m C = 105 g$

Suggest Corrections

Similar questions

Q. Consider the following statements.

1.

Specific heat capacity is the amount of heat required to raise the temperature of

1 k g

of a substance through

1

kelvin.

2.

The SI unit of specific heat capacity is

J k g^{- 1} K^{- 1}

and in CGS it is

c a l g^{- 1}^{\circ} C^{- 1}

3.

Thermal capacity is the amount of heat required to raise the temperature of a given amount of substance through

1

kelvin.
Which of the statements given above are correct?

Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 $J K g^{- 1} K^{- 1}$ . How much heat energy will be required to increase the temperature of the vessel from $25^{0} C$ to $35^{0} C$ ?

A substance is in the form of a solid at 0 °C. The amount of heat added to this substance and the temperature of the substance are plotted on the graph.

Fig, 11.9 Amount of heat (in Joule)

If the specific heat capacity of the solid substance is 500 J/kg °C, find from the graph; the specific Latent heat of fusion of the substance in the liquid state.

(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J $k g^{- 1} K^{- 1}$ .

(b) How much heat energy will be required to increase the temperature of the vessel in part(a) from 25 $^{\circ} C t o 35^{\circ} C$ ?

Q. Calculate the amount of heat required to raise the temperature of

40 k g

of compound from

10^{\circ} C

35^{\circ} C

. Specific heat capacity of the compound is

50 J / k g^{\circ} C

Join BYJU'S Learning Program

If 1050 J of heat is required to increase the temperature of 15 kg of substance from 25∘C to 35∘C. Find the thermal capacity and water equivalent of the substance?

Given:m=15kg=15×103g,ΔT=(35−25)°C=10°C,Q=1050Jwe know, Q=mCΔT, where C is specific heat capacityHence, C=QmΔT=105015×103×10=7×10−3Jg−1°C−1Thermal heat capcity =mC=15×103×7×10−3=105J°C−1And, water equivalent =mC=105g

If 1050 J of heat is required to increase the temperature of 15 kg of substance from $25^{\circ} C$ to $35^{\circ} C$ . Find the thermal capacity and water equivalent of the substance?