If 1176 = $2^{a} \times 3^{b} \times 7^{c}$ , find a, b and c.

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Solution

$1176 = 2^{3} \times 3^{1} \times 7^{2}$ = $2^{a} \times 3^{b} \times 7^{c}$

Comparing, we get a = 3, b = 1 and c = 2.

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Similar questions

1176 = 2^{a} \times 3^{b} \times 7^{c}

2^{a} \times 3^{b} \times 7^{- c}

1176 = 2^{a} \times 3^{b} \times 7^{c}

If 2 a - 3 = 5

and 3 b + 1 = 2

then find the value of (3 b - 2 a) .

1176 = 2^{a} 3^{b} 7^{c}

5544 = 2^{a} \times 3^{b} \times 7^{c} \times 11^{d} .

a + b + c + d

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