Question

The HCF of $5544=2^a\times 3^b\times 7^c\times {11}^d.$ The value of $a+b+c+d$ is:

[1 mark]

• A. 5
• B. 6
• C. 7
• D. 8

Answer 1

The correct option is C 7

Prime factorisation of $5544=2^3\times 3^2\times 7^1\times {11}^1$
⇒ a = 3, b = 2, c = 1, and d = 1
$a+b+c+d=7$