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Question

If 12x+17y=48 and 17x+12y=68, then find xy.

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Solution

Given

12x+17y=48.....×12

17x+12y=68.....×17

144x+204y=576

289x+204y=1156

145x=580

x=4

substitute x value in the 1st equation

12×4+17y=48

48+17y=48

17y=0

then

xy=40=4

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