If 15 : 20 : : 12 : 16 then using cross-multiplication, we get 15 x = x 12
Solve each of the following systems of equations by using the method of cross multiplication:
x6+y15=4,x3−y12=194.
Multiply 9x²+25y²+15xy+12x-20y+16 by 3x-5y-4 using suitable identity