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Standard VII

Mathematics

Determination of Significant Digits in a Number

If 15 @ 7...

Question

If $15$ @ $7 = 44$ , $5$ @ $4 = 18$ and $6$ 2 $! 7 = 46$ , then $17$ @ $4 = ?$

36

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42

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40

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49

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Solution

The correct option is B $42$
$(15 + 7) \times = 44; (5 + 4) \times = 18$
$(6 + 7) \times 2 = 46$ . Hence $(17 + 4) \times 2 = 42$

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If 15 @ 7=44, 5 @ 4=18 and 6 2 !7=46, then 17 @ 4=?

The correct option is B 42(15+7)×=44;(5+4)×=18(6+7)×2=46. Hence (17+4)×2=42

If $15$ @ $7 = 44$ , $5$ @ $4 = 18$ and $6$ 2 $! 7 = 46$ , then $17$ @ $4 = ?$

The correct option is B $42$
$(15 + 7) \times = 44; (5 + 4) \times = 18$
$(6 + 7) \times 2 = 46$ . Hence $(17 + 4) \times 2 = 42$