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Determination of Significant Digits in a Number

If 15 @ 7...

Question

If $15$ @ $7 = 44$ , $5$ @ $4 = 18$ and $6$ 2 $! 7 = 46$ , then $17$ @ $4 = ?$

A

36

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B

42

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C

40

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D

49

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Solution

The correct option is B $42$
$(15 + 7) \times = 44; (5 + 4) \times = 18$
$(6 + 7) \times 2 = 46$ . Hence $(17 + 4) \times 2 = 42$

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Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
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