Question

If 16.4 g of calcium nitrate is heated. Calculate the volume of ${\text{NO}}_{\text{2}}$ obtained and mass of CaO obtained.
${\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}\to {\text{Na}}_{\text{2}}{\text{O + CO}}_{\text{2}}$

Answer 1

Moles of $Ca(N{O}_3{)}_2=\frac{16.4}{16.4}=0.1$ $moles$

$Ca(N{O}_3{)}_2⟶CaO+2N{O}_2+O_2$

$0.1$ $moles$

$0.1$$moles$ $0.2$ $moles$ $0.1$ $moles$

$\to$ Mass of $CaO$ obtained $=0.1\times 56=5.6$ $gm$

$\to$ Volume of $N{O}_2$ obtained $=0.2\times 22.4=4.48$ $Litres$ at STP