Question

Question 10
If ${17}^{th}$ term of an A.P exceeds its ${10}^{th}$ term by 7. Find the common difference.

Answer 1

$Weknowthat,foranA.P.,a_n=a+(n-1)d{a}_{17}=a+(17-1)d{a}_{17}=a+16dSimilarly,a_{10}=a+9dItisgiventhat,a_{17}-a_{10}=7(a+16d)-(a+9d)=77d=7d=1$
Therefore, the common difference is 1.