Question

If -2 & -4 are the zeroes of a quadratic polynomial whose leading coefficient is 2, then find the value of (product of zeroes $\times$ coefficient of x)

• A. 96
• B. -96
• C. 16
• D. -16

Answer 1

The correct option is A 96

Given, -2, -4 are the zeroes of a quadratic polynomial.
So the quadratic polynomial can be written as: $(x+2)(x+4)=0$
$⟹x^2+6x+8=0$
Now, as the leading coefficient is 2, the quardratic polynomial will be
$2\times (x^2+6x+8=0)$
=$2x^2+12x+16=0$
So,
(product of zeroes $\times$ coefficient of x) = (-2)(-4) $\times$ 12
$=96$.