If {(2, a), (b, 8)} is an identity function, then the value of (a, b) is

(8, 2)

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(2, 8)

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(4, 1)

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(1, 4)

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Solution

The correct option is B (2, 8)

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(a^{2} - 4) x^{2} + (a^{2} - 3 a + 2) x + (a^{2} - 7 a + 10) = 0

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a - b = 0

a x^{2} + b x + c = 0

Find the value of a + b, if a $x^{2}$ + bx + c = $(2 x - 1)^{2}$ is an identity.

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