If 2 - 1 - 81- 3 - 2 - 278- 2 - 5 - 8125 then 1 - 3 - -

The correct option is A 127The rule is: #160;a #215;b=a3b3a #215;b=a3b32 #215;1=2313=812 #215;1=2313=81 #160;etc. So1 #215;3=1333=127 ...

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Intersection of Sets

If 2 × 1 = ...

Question

If 2 $\times$ 1 = 81; 3 $\times$ 2 = 278; 2 $\times$ 5 = 8125 then 1 $\times$ 3 = ?

127

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271

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126

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129

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132

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2 \times 1 = 81; 3 \times 2 = 278; 2 \times 5 = 8125

1 \times 3

\frac{(32)^{\frac{2}{5}} \times (4)^{- \frac{1}{2}} \times (8)^{\frac{1}{3}}}{2^{- 2} + (64)^{- 1 / 3}}

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x - 3 & 2 x^{2} - 18 & 3 x^{3} - 81 x - 5 & 2 x^{2} - 50 & 4 x^{3} - 500 1 & 2 & 3 \end{matrix} ∣ ∣ ∣ ∣ ∣

f (1) . f (3) + f (3) . f (5) + f (5) . f (1) =

If $3 x - \frac{1}{3 x} = 5$ , find :

(i) $9 x^{2} + \frac{1}{9 x^{2}}$

(ii) $81 x^{4} + \frac{1}{81 x^{4}}$

{(81)}^{\frac{3}{4}} - {(\frac{1}{32})}^{\frac{- 2}{5}} + 8^{\frac{1}{3}} {(\frac{1}{2})}^{- 1}

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