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Question

If (2+i) and (52i) are the roots of the. equation (x2+ax+b)(x2+cx+d)=0, where a,b,c and d are real constants, then product of all the roots of the equation is

A
40
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B
95
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C
45
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D
35
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Solution

The correct option is B 45
If one root of a quadratic equation is of the form a+ib, then other root will be aib.
So, all the roots are 2±i, 5±2i.
Product of all the roots
=(2+i)(2i)(5+2i)(52i)
=(4+1)(5+4)=5×9=45

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