If $2$ litres of butane is completely burnt the volume of $C O_{2}$ obtained under the same conditions would be:

2

lit

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4

lit

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6

lit

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8

lit

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Solution

The correct option is C $8$ lit
$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$

Molar ratio: $2 C_{4} H_{10}$ $:$ $8 C O_{2}$

$2 l i t e r s$ of oxidized butane yields $8 l i t e r s$ of $C O_{2}$

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