Question

Match the following:

A) 3 grams of ethane	1) 11.2 lit
B) 7 grams of nitrogen gas	2) 2.24 lit
C) 3.55 grams of chlorine	3) 5.6 lit
D) 8.8 grams of $C{O}_2$	4) 4.48 lit
	5) 1.12 lit

• A. A - 2, B - 4, C - 3, D - 5
• B. A - 2, B - 1, C - 5, D - 4
• C. A - 2, B - 3, C - 5, D - 4
• D. A - 4, B - 2, C - 5, D - 1

Answer 1

Answer: (C)

A - 2, B - 3, C - 5, D - 4

1 mole of a gas at STP corresponds to 22.4 L.

$3$ g of ethane corresponds to $\frac{3}{30}=0.1$ mole.

Therefore, it occupies $2.24$ L volume at STP.

$7$ g nitrogen gas corresponds to $\frac{7}{28}=0.25$ mole.

Thus, it occupies $5.6$ L at STP.

$3.55$ g chlorine gas corresponds to $\frac{3.55}{71}=0.05$ mole.

Thus, they occupy $1.12$ L at STP.

$8.8$ g carbon dioxide corresponds to $\frac{8.8}{44}=0.2$ mole. Thus, they occupy $4.48$ L at STP.

Hence, option C is correct.