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Question

If 2 millimoles of hydrated copper sulphate salt (CuSO4.5H2O) is heated to dryness, then calculate the obtained mass of anhydrous copper sulphate salt.
(Given: molar mass of Cu=63.5 g/mol)

A
0.32 g
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B
0.32 mg
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C
0.49 g
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D
0.49 mg
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Solution

The correct option is A 0.32 g
The molar mass of hydrated copper sulphate salt (CuSO4.5H2O)=63.5+32+16×4+5×18=249.5 g/mol

CuSO4.5H2OCuSO4+5H2O
On heating, we will get anhydrous copper sulphate salt i.e CuSO4

The molar mass of anhydrous copper sulphate salt=63.5+32+16×4=159.5 g/mol

As per the reaction, 1 mol of CuSO4.5H2O will give 1 mole of CuSO4

2 millimoles of hydrated copper sulphate salt will give 2 millimoles of anhydrous copper sulphate.

So, the mass of anhydrous copper sulphate salt
=159.5×2×103=0.319 g

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