Question

If $2$ moles of an ideal gas at $546$ K occupies $44.8$ L, the pressure must be.

• A. $2$ atm
• B. $3$ atm
• C. $4$ atm
• D. $1$ atm

Answer 1

Answer: (A)

$2$ atm

From gas equation, $PV=nRT$

Given that :

$V=44.8L$

$n=2$

$R=0.0821$ $L$ $atm/mol/K$

$T=546K$

$P=\frac{nRT}{V}$

$=\frac{2\times 0.0821\times 546}{44.8}$

$=2atm$

Therefore, the option is A.