If $2 %$ of the main current is to be passed through a galvanometer of resistance $G$ , then resistance of the shunt required is

\frac{G}{50}

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\frac{G}{49}

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49 G

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50 G

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Solution

The correct option is C $\frac{G}{49}$
From formulae and the conditions of the problem, we have
$\frac{I_{s}}{I} = \frac{G}{S} = \frac{.98}{.02}$

$\frac{G}{S} = \frac{98}{2} = 49$

$∴ S = \frac{G}{49}$

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If 2% of the main current is to be passed through a galvanometer of resistance G, then resistance of the shunt required is

The correct option is C G49From formulae and the conditions of the problem, we haveIsI=GS=.98.02GS=982=49∴S=G49

If $2 %$ of the main current is to be passed through a galvanometer of resistance $G$ , then resistance of the shunt required is

The correct option is C $\frac{G}{49}$
From formulae and the conditions of the problem, we have
$\frac{I_{s}}{I} = \frac{G}{S} = \frac{.98}{.02}$

$\frac{G}{S} = \frac{98}{2} = 49$

$∴ S = \frac{G}{49}$