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Question

If 2sec2θ=tanϕ+cotϕ, then one of the values of θ+ϕ is

A
π2
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B
π4
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C
π3
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D
none of these
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Solution

The correct option is C π4
2sec2θ=tanϕ+cotϕ
2sec2θ=sin2ϕ+cos2ϕsinϕcosϕ

2sec2θ=1sinϕcosϕ

2sinϕcosϕ=cos2θ

sin2ϕ=cos2θ

sin2ϕ=sin(π22θ)

2θ+2ϕ=π2
θ+ϕ=π4

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