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Question

If cotθ=12 and secϕ=53, where θ(π,3π2) and ϕ(π2,π), then the value of cot(θϕ) is

A
2
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B
12
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C
12
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D
32
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Solution

The correct option is B 12
cotθ=12secϕ=53tanϕ=sec2ϕ1tanϕ=±43
As ϕ(π2,π)tanϕ=43cotϕ=34
cot(θϕ)=cotθcotϕ+1cotϕcotθ =12×(34)+13412=12

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