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Question

If 2x+2y=2x+y, then the value of dydx at x = y = 1 is
  1. -1
  2. 1
  3. 2
  4. 0


Solution

The correct option is A -1
2x+2y=2x+y
2x.loge2+2y.loge2dydx
=2x+y.loge2(1+dydx)or2x+2ydydx=2x+y(1+dydx)dydx=2x+y2x2y2x+ydydx|x=y=1=1

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