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Mole Concept

If 20.0 g of ...

Question

If 20.0 g of $C a C O_{3}$ is treated with 20.0 g of $H C l$ , how many grams of $C O_{2}$ can be obtained according to the following reaction:
$C a C O_{3} (s) + 2 H C l (a q) ⟶ C a C l_{2} (a q) + H_{2} O (l) + C O_{2} (g)$

8.80 g

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27.4 g

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4.20 g

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13.7 g

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Solution

The correct option is A 8.80 g
Moles of $C a C O_{3}$ = $\frac{20}{100} = 0.2$
0.2 moles of $C a C O_{3}$ would require 0.4 moles $H C l$ .
Moles of $H C l$ = $\frac{20}{35.5}$ (which is greater than 0.4)
$∴ C a C O_{3}$ is the limiting reagent.
100 g of $C a C O_{3}$ produces $C O_{2} = 44$ g
20 g of $C a C O_{3}$ will give $C O_{2} = \frac{44}{100} \times 20 = 8.8$ g

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Similar questions

20.0 g

C a C O_{3}

20.0 g

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