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Preparation of Alcohols from Grignard Reagents

If 20.0 g of ...

Question

If $20.0 g$ of $C a C O_{3}$ is treated with $20.0 g$ of $H C l$ , how many grams of $C O_{2}$ can be obtained according to the following reaction:
$C a C O_{3} (s) + 2 H C l (a q) ⟶ C a C l_{2} (a q) + H_{2} O (l) + C O_{2} (g)$

8.80 g

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27.4 g

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4.20 g

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13.7 g

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Solution

The correct option is A $8.80 g$
Moles of $C a C O_{3}$ = $\frac{20}{100} = 0.2$
$0.2$ moles of $C a C O_{3}$ would require $0.4$ moles $H C l$ .
Moles of $H C l$ = $\frac{20}{35.5} = 0.56$ (which is greater than $0.4$ )
$∴ C a C O_{3}$ is the limiting reagent.
$100 g$ of $C a C O_{3}$ produces $C O_{2} = 44 g$
$20 g$ of $C a C O_{3}$ will give $= \frac{44}{100} \times 20 = 8.8 g$ of $C O_{2}$

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