If 20 ml, 2M $H_{2} S O_{4}$ is diluted to 1 Litre. Normally of the resulting solution.

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Solution

Here, Let $M_{1}$ (molarity $H_{2} S O_{4}$ )=2M, $V_{1}$ (volume of $H_{2} S O_{4}) = 20 m l = 0.02 L$ , $V_{2}$ (volume of solution)= $1 L$ and $M_{2} (molarity of resulting solution) = ?$

Therefore, $M_{1} \times V_{1} = M_{2} \times V_{2}$

$M_{2} = 0.04 M$

$N o r m a l i t y = M_{2} \times n$ , here n is number of $H^{+}$ ions an acid can donate

$N o r m a l i t y = 0.04 \times 2 = 0.08 N$

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If 20 ml, 2M H2SO4 is diluted to 1 Litre. Normally of the resulting solution.

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If 20 ml, 2M $H_{2} S O_{4}$ is diluted to 1 Litre. Normally of the resulting solution.