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Question

if 250J of work is done in sliding a 5kg block up an inclined plane of height 4m work done against fiction g=10ms−2)

A
50J
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B
100J
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C
200J
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D
Zero
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Solution

The correct option is A 50J
For calculating work done when friction is involved,
Total work done(W)is equal to Work done against friction(W1)+ Work done against gravity(W2)

Given:

Total work is done (W)=250J

Mass(m)=5kg

Therefore, Weight(w)=5×10=50N
Height(h)=4m

W=W1+W2
W=W1+(w×h)
250=W1+50×4)
W1=250200
W1=50
Hence work done against friction is 50J

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