Question

If 28 gm of nitrogen gas consists of $6.022\times {10}^{23}$ molecules. Then how many gram of nitrogen will have $4.22\times {10}^{23}$ molecules.

• A. 21 gm
• B. 17.21 gm
• C. 19.61 gm
• D. 22.34 gm

Answer 1

The correct option is C 19.61 gm

28 gm contains $6.022\times {10}^{23}$ molecules

So, $4.22\times {10}^{23}$ molecules will have $\frac{28\times 4.22\times {10}^{23}}{6.022\times {10}^{23}}$
= 19.61 gm.